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x-3/x+3+x+3/x-3=2x(x+1)/x^2-9
We move all terms to the left:
x-3/x+3+x+3/x-3-(2x(x+1)/x^2-9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x^2-9)!=0We add all the numbers together, and all the variables
x∈R
2x-3/x+3/x-(2x(x+1)/x^2-9)=0
We calculate fractions
We do not support expression: x^3
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